What array is this C function expecting?

Shay · 05-07-2009, 04:54 PM

I want to use a function that starts out:

Code:

REAL some_func(some_array)
  REAL *some_array;

I'm trying to call this with:

Code:

float my_array[2];
my_array[0] = 1;
my_array[1] = 2;
some_func(my_array);

Doesn't work. some_array ends up filled with different numbers.
Any suggestions?

-Shay

raconteur · 05-07-2009, 06:16 PM

I think you may be mixing languages, perhaps... it isn't clear from your example.
REAL is a data type in most java implementations, but not c/c++.
Unless you have typedef'd it somewhere you should also be getting a host of other errors.

This should work:

Code:

#include <stdio.h>

float some_func(float *some_array);

int main(int argc, char **argv)
{
  float my_array[2];
  my_array[0] = 1.0;
  my_array[1] = 2.0;

  float val = some_func(my_array);

  printf("val=%f\n", val);
}

float some_func(float *some_array)
{
  return some_array[0] + some_array[1];
}

rriggs · 05-07-2009, 06:52 PM

It looks like you are trying to use ancient C code. Hard to tell without more context.

chrism01 · 05-07-2009, 09:35 PM

Speaking of mixing langs (and you are doing numeric stuff), sounds like you're mixing FORTRAN with C. REAL is a type in FORTRAN.