Hi ! All
Trying to pick up shell script. When I do :

mis="123"
echo $mis

It return "123"

Now, if I want to return the the result "mis" instead of value "123". How can I do that ?

I am beginner, appreciate all the experts here to help.

Regards,
x2000koh

Simple: you have to escape (take away special meaning) the quotes.

XXX=\"xxx\" echo $XXX

Gives "xxx"

You may also use single quotes. Everything inside is taken literally, without any special meaning, ie XXX=' "xxx" '

If you want to surround text with single quotes, you have to use the backslash escape method.

Recommended reading:

bash(1) # that is the man page in section 1. Try man bash
bash info documentation
Advanced Bash Scripting HOWTO (start out simple. See www.tldp.org)

You want the name of the variable? Just:

You already KNOW the name of the variable, as you chose it when you coded it ... I don't see how this is very useful.

strike
Thanks for reply ! to let you know the full picture of what I am going to do.

1) I have written a script to evaluate the user group (GID). It only return the GID in number. But I want it to return a group name.

My script is as follow.

addlink.sh
-------------
group=$(id -g)
echo $group


when I run the above it return "511". let say GID 511 is mis group. How can I convert the 511 to show mis. (can I echo $511 ?)

2) softlink base on department

if GID is mis
ln -s /home/dept/mis mis
end if

3) calling a script
How can I call another script from my existing program ? Which command to use ?

I want the .bash_profile to call the addlink.sh when user login.

The addlink.sh is located at /home/maple
The .bash_profile is located at /home/maple/$USER

appreciate your help.

x2000koh

To lookup a group, based on numwerical GID, use id -gn. (or grep if youre feeling masochistic)

To call another script, see my reply in the other thread you started