trying to determine the size of all files in a directory
 

How would I write a script that will determine if all the files in a directory are below say 650mb, and if they are more than 650mb maybe say some sort of error?
Thanks for all help

try "du -s -k /some/directory/here" and parse the result

I'm sorry but I dont even know what parse the results means?
thanks for the help though

read up on "find", e.g

find /directory -size +650000k

will find all files that are over 650mb, then you can use an -exec option (or a thousand other ways) to run a command on each of those files or such like.

for details on beginning scripting, read through some of the Rute guide in my signature, and the bash-scripting howto at tldp.org

this is what I am doing, I am writing a script to burn audio cds, so now it will convert all mp3 files in .wav files normalize them and burn them but I have no clue if there are too many files in the directory to make the cd, so I would like it to check and tell me if there are to many files in that directory...sorry I waited till now to tell you all this.

so it's the total size that matters... nice to finally know what we're meant to be solving.

so just check a du output. assuming that there will never be any subdirectories around, this should work.

thanks again for the help that should work for me thanks and sorry for not explaining it the right way.

sorry for this but everytime I run the script it tells me that there is more than 650mb when there is 606mb in the directory? Thanks for the help and patients