This must be a very basic Lisp question.
But after all I am a Lisp beginner, so I beg your pardon -
.
Let us say I define a list as follow :
(setq VLX '(0 1 2 3 4 5 6 7 11 13 17 19))
The interpreter replies :
(0 1 2 3 4 5 6 7 11 13 17 19)
and my list is defined.
Now, here is my question :
Which function call should I make to get this answer ?
(0 1 2 3 4 5 6 7 11 13 17 19)
In other word I want the same as if I do :
(reverse (reverse VLX))
or
(car (list VLX))
but in a simpler way.
Thanks in advance for any tip.
