[SOLVED] the IP on the second address

NetRock · 09-24-2010, 08:39 AM

Hi all,

got stuck on the followings and need your help, please.

when i do nslookup by name (loop2) i get the followings:

Code:

#nslookup loop2

server: mainsrv-local.local
address: 192.168.0.1

server: loop2-local.local
address: 192.168.20.36

i am interested in the second address (address: 192.168.20.36) have output only the ip address. so to get only 192.168.20.36.
tried different ways with sed and awk but so far nothing worked any suggestions? getting the ip from the second address makes it difficult.

thank you in advance.

druuna · 09-24-2010, 08:43 AM

Hi,

One way of doing this:

nslookup loop2 | sed -n '$s/address: //p'

Hope this helps.

kurumi · 09-24-2010, 08:44 AM

Code:

nslookup ... | ruby -ane 's=$F[-1].chomp if /address/;END{puts s}'

eco · 09-24-2010, 08:47 AM

Hi,

Maybe using the host command might be easier for you. I think nslookup has been replaced by host or dig for a while now.

NetRock · 09-24-2010, 09:06 AM

thanks for the replies.

i used:

Quote:

nslookup loop2 | tail -4 | grep -ir "Address" | awk -F ":" '{print $2}'

it works fine but do not like using the tail -4 as it could change, any better idea?

also, tried :

Quote:

nslookup loop2 | sed -n '$s/address: //p'

but no go...!!

Thanks

grail · 09-24-2010, 09:19 AM

Always with you wanting to be complicated ... lol

Code:

nslookup loop2 | sed -n '/loop2/{n;s/address: //p}'

nslookup loop2 | awk -F"[ \t]*:[ \t]*" '/loop2/{getline;print $2;exit}'

nslookup loop2 | awk '/loop2/{getline;gsub(/^.* /,"");print;exit}'

NetRock · 09-24-2010, 12:09 PM

AS always Thanks grail.