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Old 07-05-2009, 11:59 AM   #1
phillip58
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Registered: Jul 2009
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syntax error near unexpected token "fi"


I'm having problems executing this script:
the "syntax error newar unexpected token "fi" comes up. I have tried all that I know. thanks in advance.


#!/bin/bash
#
# START:./numbers.sh $1 $2 $3
#
# $1=$1
# $2=$2
# $3=$3

# "Check number of command line arguments."
# "Three numbers not present print error message."
if [ $# -ne 3 ];
then
# echo "$0: Three numbers must be given"

# echo "Correct number of command line arguments entered."

fi

if [ $1 -gt $2 ] && [ $1 -gt $3 ];
then
echo -e "\033[32m "The first number is the largest"
fi

if [ $2 -gt $1 ] && [ $2 -gt $3 ];
then
echo "The second number is the largest"
fi

if [ $3 -gt $1 ] && [ $3 -gt $2 ];
echo -e "\033[42m "The third number is biggest!"

fi
echo -e "\033[0m Script execution complete"

done
 
Old 07-05-2009, 12:12 PM   #2
kirukan
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Refer this
http://www.freeos.com/guides/lsst/ch03sec03.html
 
Old 07-05-2009, 12:20 PM   #3
colucix
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You missed then in the last if/then. done at the end of the script means nothing and gives error. Also check carefully the double quotes in the echo statements: they must be in pairs.
 
Old 07-05-2009, 01:00 PM   #4
XavierP
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Moved: This thread is more suitable in Programming and has been moved accordingly to help your thread/question get the exposure it deserves.
 
  


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