strlen problem

salahuddin_66 · 11-13-2005, 02:21 AM

could some one tell me why it is not working.
i am learning C.

thanks

Code:

#include <stdio.h>
#include <string.h>

void converge (char *targ, char *src);

int main (void)
{
	char target [80] = "XXXXXXXXXXXXXXXXXXXXXXXXXXX";

	converge (target, "This is a test of converge.");
	printf("Final string: %s\n", target);

	return 0;
}

void converge (char *targ, char *src)

{
	int i, j;
	printf ("%s\n", targ);
	for (i=0, j=strlen(src); i<=j; i++, j--)
{
	targ [i] = src [j];
	targ [i] = src [j];
	printf("%s\n", targ); 
					}
}

TruongAn · 11-13-2005, 03:43 AM

Exactly, how do you mean when you said it didn't work?
We don't know what are you intend to do with these code, so we cannot say anythings.
The only strange I found that you have add two line
targ [i] = src [j];
Only one is enough, however it is not a problem, your code can work with two or more line

salahuddin_66 · 11-13-2005, 04:21 AM

thanks a lot

now ok

it was showing

XXXXXXXXXXXXXXXXXXXXXXXXXXX

Final string:
salahuddin@debiantesting:~/C$

now ok
salahuddin@debiantesting:~/C$ ./a.out
XXXXXXXXXXXXXXXXXXXXXXXXXXX
TXXXXXXXXXXXXXXXXXXXXXXXXXX
ThXXXXXXXXXXXXXXXXXXXXXXXX.
ThiXXXXXXXXXXXXXXXXXXXXXXe.
ThisXXXXXXXXXXXXXXXXXXXXge.
This XXXXXXXXXXXXXXXXXXrge.
This iXXXXXXXXXXXXXXXXerge.
This isXXXXXXXXXXXXXXverge.
This is XXXXXXXXXXXXnverge.
This is aXXXXXXXXXXonverge.
This is a XXXXXXXXconverge.
This is a tXXXXXX converge.
This is a teXXXXf converge.
This is a tesXXof converge.
This is a test of converge.
Final string:This is a test of converge.

after

targ [i] = src [i];
targ [j] = src [j];