Starting a program from a shell script

Suinatsa · 04-09-2005, 06:09 AM

Hey guys,

I have been trying to write a shell script which is able to run a little programm.

ping -c 2 192.168.1.51
if [$? !=0] ; then
wol --host=192.168.1.1 90:50:A1:EF

0:53
echo "Starting up Host"
fi
Thats what I got so far. What I want to do is that the script pings one of my computers in my network.
Whenever it fails I want the script to start the program "wol" which starts up the remote computer by the wake on lan function.

I am a noob in shell programming so it is a minor error most probably. I guess the line

wol --host=192.168.1.1 90:50:A1:EF

0:53

has to be different. It is the whole command which has to be executed.

Thx

Suinatsa

david_ross · 04-09-2005, 09:06 AM

Are you getting an error when you try to run the script? Perhaps you could tell us what it is.

osvaldomarques · 04-17-2005, 01:16 AM

Hi Suinatsa,
Looking your script, I guess it is logically correct. However, you must get a syntax error in the line:

Code:

if [$? !=0]

The character "[" is a symbolic link to /usr/bin/test. If you read "man test", you'll see:
1 - when using the alternative "[" "]" you have to separate both the brackets by space;
2 - numerical comparisons are specified by "-eq" for "equal to", "-ne¨ for "not equal to".
So, this line should be:

Code:

if [ $? -ne 0 ]; then

I don't know the "wol" command but, the syntax is the same as you use in interactive mode.

Cheers,

Osvaldo