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Started programs with one script. Want to kill them with another

I started several programs with the following script:

Code:

front_end1 input1_a &

sleep 4

program2 input2_a &

program2 input2_b &

program2 input2_c &

program5 input5_a &



program6 &

I would like to be able to shut them all down as well. Is there a way to do this with a second script? I don't know how to do this because the second script would not know the PIDs. Is there a way I can do all of this with just one script?

You can kill programs by name as well as by pids. See man killall.

You can also use the following:

kill `ps aux | grep PROGRAM | awk "${2}"`

Most likely, I jacked up the quotation marks because I am at work and am using a *gag* windows machine.....so just fix the awk command up and there you go!

Assuming that you're using bash, you're looking for the "jobs" builtin command. For instance:

Code:

#!/bin/bash



AWK="/usr/bin/awk"

DU="/usr/bin/du"



${DU} -hs /home/username/temp &

${DU} -hs /home/username/Documents &

${DU} -hs /home/username/Downloads &



job_pids=$( jobs -l | ${AWK} '{print $2}' )

for job_pid in ${job_pids} ; do

  echo "job_pid = ${job_pid}"

done



exit 0

The jobs builtin will display information about each process spawned by the environment the shell script was using. Use the '-l' option to have the PID listed for each job. For more info, type man bash and search for "SHELL BUILTIN COMMANDS" (e.g., in the man page, press the forward slash '/', type 'SHELL BUILTIN COMMANDS', and press Enter). You will need to continue scrolling down for a while, but you'll get there.

When using the '-l' option, the PID is displayed in the second column (hence the awk command).

You can then save the PIDs to a file. Your other script can read the PIDs from that file, kill the PIDs listed, and then delete the PID file.