splitting numbers and characters from an array of characters.

trscookie · 11-13-2008, 02:45 AM

Hello all,

I have a string in c that I am trying to split the numbers and letters into their corrisponding variable, could someone explain how this is possible please i.e:

pass in a char of "123abc"

and return two values of "123" as and integer and another variable of "abc"?

Many thanks in advance.

maradnus · 11-13-2008, 03:13 AM

You can go through the string related functions like

strcpy, strncpy, etc

use man strcpy for more information.

YOu can also think of atoi() function.

----------------
OR

you can write your own function to do that.
void parsestring(const char *src, char *no, char *text);

trscookie · 11-13-2008, 03:25 AM

Hi, cheers for the response. its not the conversion that i cant work out, its the actual splitting of the string( on the basis that i do not know how long the numbers, or chars are in the value ) i.e 123abc or 1234cd etc:

Code:

if( splitstring( charvalue, numvalue, "123abc" )==TRUE )
{}

Code:

int splitstring( char *p_newchar, char *p_newnum, char *p_text )
{
int  l_newnum        = 0;
char l_tmpnum[10]    = "";
char l_newchar[10]   = "";

for( lenofnumber )
{
  l_tmpnum=intvalue + nextint;
}

l_newnum=atoi( l_tmpnum );

for( lenofchar )
{
  l_newchar=charvalue + nextchar;
}

...

}

pinniped · 11-13-2008, 03:53 AM

Well, you obviously have to go through the whole string one character at a time and decide if it's a number or a letter.

You might find some more clues in ctype.h

maradnus · 11-14-2008, 09:20 AM

I hope the data format is fixed like this: NNNNNNNNNXXXXXXXX
that is first part is a number and the next part is the text.

maradnus · 11-14-2008, 09:33 AM

Use the following statement:

Code:

char text[100];
strcpy(text,"1234asdfk");
int n = atoi(text);
printf("%d",n);

maradnus · 11-14-2008, 09:34 AM

Code:

#include <stdio.h>
#include <ctype.h>
#include <stdlib.h>
void pstring(const char *src, int *);
int main(int argc, char *argv[])
{
        int n;
        char t[100];
        printf("\n Enter Text:");
        scanf("%s",t);
        pstring(t,&n);
        exit(0);
}


void pstring(const char *src, int *no)
{
        int result;
        int i=0;
        int sum = 0;
        while(src[i]!='\0'){
                if(isalpha(src[i]))break;
                sum = sum*10+(src[i]-'0');
                i++;
        }
        *no = sum;

}