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Simple bash script programming problem

I am very new to script programming...
I want to read two parameters 1012 and 2345 from pattern

ftp=(1012,2345)

How can I make it?

Thanks!

Code:

s="I want to read two parameters 1012 and 2345 from pattern"



# 0. fixed field, bash:

f=(${s}); ftp="${f[6]} ${f[8]}"



# 1. fixed field, +awk:

echo "$s"|awk '{print $7, $9}'



# 2. search fields, bash:

f=(${s}); for n in `seq 0 ${#f[@]}`; do

 case "${f[$n]}" in [0-9]*) echo "${f[$n]}";; esac

done



# 3. replacement, the wrong way ;-p

f="${s//[a-z]/}"

It all depends on where and how you want to use it.

Code:

function help() { echo "Bash scripting guides:

http://www.tldp.org/HOWTO/Bash-Prog-Intro-HOWTO.html 

http://www.tldp.org/LDP/Bash-Beginners-Guide/html/index.html 

http://www.tldp.org/LDP/abs/html/ 

http://wooledge.org/mywiki/BashFAQ?action=show&redirect=BashFaq 

http://wooledge.org/mywiki/BashPitfalls"; }

Wow...the answer is too much to me.
Actually, I just want to get number 1012 and 2345 from pattern
ftp=(1012, 2345), which is fixed...

Thank you again

Quote:

Originally Posted by unSpawn (Post 3037677)

Code:

s="I want to read two parameters 1012 and 2345 from pattern"



# 0. fixed field, bash:

f=(${s}); ftp="${f[6]} ${f[8]}"



# 1. fixed field, +awk:

echo "$s"|awk '{print $7, $9}'



# 2. search fields, bash:

f=(${s}); for n in `seq 0 ${#f[@]}`; do

 case "${f[$n]}" in [0-9]*) echo "${f[$n]}";; esac

done



# 3. replacement, the wrong way ;-p

f="${s//[a-z]/}"

It all depends on where and how you want to use it.

Code:

function help() { echo "Bash scripting guides:

http://www.tldp.org/HOWTO/Bash-Prog-Intro-HOWTO.html 

http://www.tldp.org/LDP/Bash-Beginners-Guide/html/index.html 

http://www.tldp.org/LDP/abs/html/ 

http://wooledge.org/mywiki/BashFAQ?action=show&redirect=BashFaq 

http://wooledge.org/mywiki/BashPitfalls"; }

in this specific case you could have

Code:

pattern="ftp=(1012, 2345)"

pattern="${pattern//[a-z,=\(\)]/}"

if you played with the examples.