shell script - while loop with multiple conditions
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i haven't tried it yet but I'm not aware of "problems" in getting out of the loop if I'll do it this way.
Will the loop continue even when none of the conditions is true? Is there a different way I can do it to avoid the problems?
Once you enter the loop, you cannot leave it if you depend on the content of the value variable (the while statement will always be true). This isn't a bad thing per se, it depends on what you want to do.
Without knowing what it is you are trying to do it's kinda hard to give advise on how to proceed. And like I stated before, it could be that this is the correct sollution to your problem.
Yes, break will do the trick.
What I'm trying to do is to read a value from the user but I want to restrict him to 3 values only.
So inside the loop i have the 3 values as i stated beore and inside the loop i have the read command
the user need to enter a value but he has to choose one out of three.
My loop will ensure that if he hasn't entered one of those three then he will have to try again and again until he will enter one of those three.
while [ "$value" != "val1" || "$value" != "val2" || "$value" != "val3" ]