ProgrammingThis forum is for all programming questions.
The question does not have to be directly related to Linux and any language is fair game.
Welcome to LinuxQuestions.org, a friendly and active Linux Community.
You are currently viewing LQ as a guest. By joining our community you will have the ability to post topics, receive our newsletter, use the advanced search, subscribe to threads and access many other special features. Registration is quick, simple and absolutely free. Join our community today!
Note that registered members see fewer ads, and ContentLink is completely disabled once you log in.
If you have any problems with the registration process or your account login, please contact us. If you need to reset your password, click here.
Having a problem logging in? Please visit this page to clear all LQ-related cookies.
Introduction to Linux - A Hands on Guide
This guide was created as an overview of the Linux Operating System, geared toward new users as an exploration tour and getting started guide, with exercises at the end of each chapter.
For more advanced trainees it can be a desktop reference, and a collection of the base knowledge needed to proceed with system and network administration. This book contains many real life examples derived from the author's experience as a Linux system and network administrator, trainer and consultant. They hope these examples will help you to get a better understanding of the Linux system and that you feel encouraged to try out things on your own.
Click Here to receive this Complete Guide absolutely free.
i am trying to write a scrpt (eg : me.sh) and pass arguments to it so that if it is executed on the command prompt "me.sh -g" i should get the groupid of the user who has issued this
command. Similarly if some one issues "me.sh -u" i should get the userid.
You don't need an explicit exit. The exit code will be set automatically depending on the status of the scripts exit ('0' for success, non-zero otherwise). You can check the scripts exit status with "echo $#"
Finally, you have:
fi fi fi
which is not correct syntax.
I would help you more specifically but I suspect this is homework
Yes i do need to know the GID and UID, but only if the user asks for either of them or both. For Example the script is called "me.sh" so the user should be able to pass argument to this script, like this :-
"me.sh -g" to know the groupid or
"me.sh -u" to know the userid or
"me.sh -g -u" to know both.