LinuxQuestions.org - Shell script: How to include a variable between apostrophes within a command

- Programming (https://www.linuxquestions.org/questions/programming-9/)

- - Shell script: How to include a variable between apostrophes within a command (https://www.linuxquestions.org/questions/programming-9/shell-script-how-to-include-a-variable-between-apostrophes-within-a-command-531064/)

guarriman

02-21-2007 11:41 AM

Shell script: How to include a variable between apostrophes within a command

Hi.

I'm trying to find some words within my directory and created a text file containing them which is read by my shell script:

Code:

#!/bin/bash

var=`cat words.txt`

for i in $var; do

        echo $i

        find -type f -print0 | xargs -r0 grep -F '$i'

done

But it searches "$i" (dollar sign with 'i'), and not the word. How to do it?

Thank you very much.

asommer

02-21-2007 11:43 AM

Try double quotes around your variable "$i".

andrews-mark

02-21-2007 12:01 PM

the double quotes interpret shell variables while the single quotes do not

for example, in the bash shell

Code:

> x='foobar'

> echo $x

foobar

> echo "$x"

foobar

> echo '$x'

$x

-mark

bigearsbilly

02-23-2007 03:12 AM

you are searching idividually throught the words file????

Code:

find . -type f | xargs -n9 grep -f words.txt

All times are GMT -5. The time now is 10:58 PM.