Selecting output as a directory path

prravin1 · 03-02-2012, 01:57 AM

I have a script which take a path of a folder as an argument and a path for the output.

Ex- Myscript.sh /bin/apps/sample /bin/apps/

Input - /bin/apps/sample ($1)
Output - /bin/apps/ ($2)

Now the output should always be stored in /bin/apps/ ie one directory backwards of input directory. Please remember that the input and output directory paths vary as per user so i need a universal code which can perform the following operation.

druuna · 03-02-2012, 02:06 AM

Hi,

Are you looking for this:

Code:

$ input="/a/b/c/d"
$ output="${input%/*}"
$ echo $output
/a/b/c

This ${input%/*} strips everything after the last / (including /).

Have a look at man bash, the Parameter Expansion section for details.

Hope this helps.

prravin1 · 03-02-2012, 02:16 AM

Quote:

Originally Posted by druuna

Hi,

Are you looking for this:

Code:

$ input="/a/b/c/d"
$ output="${input%/*}"
$ echo $output
/a/b/c

This ${input%/*} strips everything after the last / (including /).

Have a look at man bash, the Parameter Expansion section for details.

Hope this helps.

I think its working. Thanks.

druuna · 03-02-2012, 02:17 AM

You're welcome

BTW: Can you put up the [SOLVED] tag.
first post -> Thread Tools -> Mark this thread as solved

prravin1 · 03-02-2012, 05:28 AM

Quote:

Originally Posted by druuna

You're welcome

BTW: Can you put up the [SOLVED] tag.
first post -> Thread Tools -> Mark this thread as solved

Sorry to make this thread as unsolved again. Actually after the output directory is created, a third script requires its location and need to enter it.

How should i located the exact output directory created my the script as there will be so many output folders in the location?

How will a second script know the location of the output of first script?

druuna · 03-02-2012, 06:37 AM

Hi,

Quote:

Originally Posted by prravin1

How should i located the exact output directory created my the script as there will be so many output folders in the location?

How will a second script know the location of the output of first script?

Assuming that the second script is not started from within the first script or piped: You need to store the directory into a separate, temporary file. Normally independent scripts are not aware of each other.

Code:

#!/bin/bash
# get the desired directory (/a/b/c in this case)
input="/a/b/c/d"
output="${input%/*}"
# maybe other code goes here
.
.
# store the directory in a temp file
echo ${input} > /tmp/script1.out

The second script needs to get the info from that file:

Code:

#!/bin/bash
# get dir info
input="$(cat /tmp/script1.out)"
# rest of the code for script 2
.
.

Hope this helps.

prravin1 · 03-02-2012, 06:42 AM

Quote:

Originally Posted by druuna

Hi,
Assuming that the second script is not started from within the first script or piped: You need to store the directory into a separate, temporary file. Normally independent scripts are not aware of each other.

Code:

#!/bin/bash
# get the desired directory (/a/b/c in this case)
input="/a/b/c/d"
output="${input%/*}"
# maybe other code goes here
.
.
# store the directory in a temp file
echo ${input} > /tmp/script1.out

The second script needs to get the info from that file:

Code:

#!/bin/bash
# get dir info
input="$(cat /tmp/script1.out)"
# rest of the code for script 2
.
.

Hope this helps.

Thanks. Will try the above method. Can you have a look at my latest thread which is more brief about what i exactly want to achieve?