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Old 08-06-2006, 02:08 PM   #1
hfawzy
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Registered: Aug 2002
Location: Egypt
Distribution: Debian Sarge, Slackware 10.0
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sed trouble


Hi,
I'm having some troubles replacing a string in a file using sed.
Here is what I want : I want to replace the first match occured with 1 the second match with 2, etc... till the end of the file.
For example if the file looks like this :
Quote:
Sample text..
Here is some text...
Some text
I want it to look like this after applying the above replacing system to string "text":
Quote:
Sample 1..
Here is some 2...
Some 3
How can I do that ?
Thank you.
 
Old 08-06-2006, 02:32 PM   #2
sdexp
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Registered: Sep 2003
Location: USA
Distribution: Ubuntu Linux
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Code:
i=1
for word in `echo "Sample text..
Here is some text...
Some text"`
do 
   echo $word | sed 's/text/$i/g'
   if [ $word = "text" ]
   then
      let "i+=1"
   fi
done
I haven't tested it, but think it will work, maybe with a few modifications.

Last edited by sdexp; 08-07-2006 at 10:36 PM.
 
Old 08-06-2006, 03:20 PM   #3
hfawzy
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Original Poster
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Thanks for the reply. This almost solved the problem.
Problem is that $i incrments, even if the word is not "text". I want to increment $i only if "text" is found and has been replaced.
 
Old 08-06-2006, 05:21 PM   #4
homey
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Registered: Oct 2003
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Will this work for you?
Code:
perl -ne 'print if /text/' < file.txt | perl -pe 's/text/$./'
 
Old 08-06-2006, 05:36 PM   #5
spirit receiver
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Registered: May 2006
Location: Frankfurt, Germany
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I think this is what hfawzy wants. It makes a backup of the original file.
Code:
perl -i.bak -e '$i=1; while(<>){$i++ if(s/text/$i/);print}' filename
 
Old 08-07-2006, 10:37 PM   #6
sdexp
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Registered: Sep 2003
Location: USA
Distribution: Ubuntu Linux
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Yes, you caught me dosing off there hfawzy.

I did correct it though in that post.

Here it is again:

Code:
i=1
for word in `echo "Sample text..
Here is some text...
Some text"`
do 
   echo $word | sed 's/text/$i/g'
   if [ $word = "text" ]
   then
      let "i+=1"
   fi
done
 
  


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