[SOLVED] SED: replace all coincidences only from a position upto another
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awk -F "" 'OFS="";{for (j=5;j<= 10;j++) if ($j=="x") $j="y"}'1
Daniel B. Martin
Thanks! Works great.
I am facing an unexpected need: same file but with variable fields tab separated instead of fixed width.
I can not use the lenght because of the variable size of every field, and need to "count" fields, in order to replace "x" for "y" in fields from #2 to #8.
Thanks!
PS: will mark as solved as the original question in fact is.
I am facing an unexpected need: same file but with variable fields tab separated instead of fixed width.
I can not use the length because of the variable size of every field, and need to "count" fields, in order to replace "x" for "y" in fields from #2 to #8.
Please provide a sample input file and a corresponding output file. Tell which character separates fields (blank, tab, etc.).
I am facing an unexpected need: same file but with variable fields tab separated instead of fixed width.
I can not use the length because of the variable size of every field, and need to "count" fields, in order to replace "x" for "y" in fields from #2 to #8.
To replace all "e" with "E" in blank-delimited fields 2 through 8, try this ...
'Prophet!' said I, 'thing of Evil! - prophEt still, if bird or devil!
By that HEavEn that bEnds abovE us - by that God we both adore -
Tell this soul with sorrow ladEn if, within the distant Aidenn,
It shall clasp a saintEd maidEn whom thE angels named Lenore -
Clasp a rarE and radiant maidEn, whom thE angels named Lenore?'
Quoth thE ravEn, 'NEvErmorE.'
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