Running a shell file multiple times with different arguments each time in a loop

kvr2277 · 08-18-2011, 09:10 AM

Hi,

I'm a newbie to shell scripting and am facing the below problem

"I have a shell file run.sh and it has to run multiple times with different arguments passed each time.
Eg:
run.sh abc1
run.sh abc2
run.sh abc3
run.sh abc4
.
.
run.sh abc28"

So, if I consider this in Java terms, it might need a loop programming (for loop?)

Can somebody help me sail through the above problem?

TobiSGD · 08-18-2011, 09:22 AM

Your mentioning of the for loop is absolutely correct. Tho answer for your question would be:

Code:

for i in {1..28}
do
    run.sh abc$i
done

For more info about bash scripting you might want to have a look at http://tldp.org/LDP/abs/html/.

crts · 08-18-2011, 09:22 AM

Welcome to LQ,

do you mean something like this?

Code:

for i in {1..4}; do
  /path/to/run.sh "abc${i}"
done

You can also use any arbitrary number of arguments to the for-loop:

Code:

for arg in "argument 1" "argument 2" "argument ...";do
  echo "${arg}"
done

Hope this helps.

kvr2277 · 08-18-2011, 09:29 AM

Thank you. LQ is pretty fast.