[SOLVED] Run a C program from bash script

bvkim · 05-09-2010, 09:36 PM

I'm trying to write a bash script that helps me building C program then run the C program but I don't know how to make it run.
I did like this

Code:

#!/bin/sh

# assuming I've built C program '$output' successfully

# then call C program from script
`./$output` # error here, "command not found"

ArfaSmif · 05-09-2010, 10:28 PM

Quote:

Originally Posted by bvkim

I'm trying to write a bash script that helps me building C program then run the C program but I don't know how to make it run.
I did like this

Code:

#!/bin/sh

# assuming I've built C program '$output' successfully

# then call C program from script
`./$output` # error here, "command not found"

Code:

#!/bin/sh

output

This will work if output is executable and also in your PATH variable. Otherwise, simply put the full pathname to output in your script, for example /home/user/bin/output (it still has to be executable though.

bvkim · 05-09-2010, 11:20 PM

@ArfaSmif:
still error

Code:

# Testing output
execute="."`pwd`"/$output"
echo "$execute" # full path name correct
$(execute) # error: execute: command not found
execute # error: execute: command not found

grail · 05-09-2010, 11:23 PM

echo is a command.
$execute is a variable.

Try maybe - eval "$execute"

bvkim · 05-10-2010, 12:02 AM

Quote:

Originally Posted by grail

echo is a command.
$execute is a variable.

Try maybe - eval "$execute"

Thanks, eval() is what i'm looking for.
Problem solved!

paulsm4 · 05-10-2010, 12:35 AM

bvkim -

As a courtesy, please be sure to:
a) thank grail (the blue "thumbs up" icon)
... and ...
b) mark your thread "solved" (makes it easier for other folks with the same problem to find your question, and the corresponding solution)

Thank you in advance .. PSM