LinuxQuestions.org - Replace file name

LinuxQuestions.org (/questions/)

- Programming (https://www.linuxquestions.org/questions/programming-9/)

- - Replace file name (https://www.linuxquestions.org/questions/programming-9/replace-file-name-4175520484/)

rohit_shinez

09-29-2014 09:29 AM

Replace file name

Hi,

I am having a files in my directory like this:

Code:

2014 1049_file1.txt

2014 1050_file2.txt

2014 1110_file3.txt

2014 1145_file4.txt

2014 2049_file5.txt

I need to replace the above file names like this without changing the content of filename:

Code:

file1.txt

file2.txt

file3.txt

file4.txt

file5.txt

I tried something like this but didn't workout:

Code:

for i in *.txt

do

mv $i ${*_i}

done

schneidz

09-29-2014 09:32 AM

since you have stupid spaces in your original filenames maybe you need to put quotes around them so that the shell can interpret them correctly (what is the error you are getting -- file not found ?) ?

there is prolly a better way but this is my quick-and-dirty hax with awk[untested]:

Code:

for i in *.txt

do

mv $i `echo $i | awk -F _ '{print $2}'`

done

rohit_shinez

09-29-2014 10:05 AM

Hi,

the above didn't work its giving error and moreover my code gave error like
-bash: ${*_i}: bad substitution

NevemTeve

09-29-2014 10:56 AM

Code:

for i in *.txt; do

    mv -- "$i" "${i#*_}"

done

teckk

09-29-2014 03:57 PM

My 2 cents

Another way to remove spaces in filenames in a folder

Code:

for i in *.txt; do mv "$i" ${i// /}; done

If those are all the same you also could remove the first 10 characters in the filenames.

Code:

for i in *.txt; do mv $i $(echo $i | sed 's .\{10\} '); done

Code:

for i in *.txt; do mv $i $(echo $i | cut -c 10-); done

suicidaleggroll

09-29-2014 04:57 PM

Quote:

Originally Posted by teckk (Post 5246505)

If those are all the same you also could remove the first 10 characters in the filenames.

Code:

for i in *.txt; do mv $i $(echo $i | sed 's .\{10\} '); done

Code:

for i in *.txt; do mv $i $(echo $i | cut -c 10-); done

Code:

for i in *.txt; do mv "$i" "${i:10}"; done

schneidz

09-30-2014 09:05 AM

Quote:

Originally Posted by rohit_shinez (Post 5246332)

Hi,

the above didn't work its giving error and moreover my code gave error like
-bash: ${*_i}: bad substitution

the only way to fix the error is to know what the error is ?

All times are GMT -5. The time now is 01:21 AM.