Renaming array elements in bash

bryan.out.there · 05-26-2006, 09:55 AM

Hullo World,

Does bash have a foreach loop which allows you to work on each element in that array? (as you can in Perl for instance).

I've tried:
stripped_file+=`basename "${filename[$i]}" .ext`" "
and:
stripped_file=( ${stripped_file[@]} `basename "${filename[$i]}" .ext`".newext "

but these produce single element arrays without separating on whitespace.

Failing that - how do you split an array on whitespace? (as in perl's split).

Thanks a bunch,

Bryan.

Hobbletoe · 05-26-2006, 11:45 AM

Check out the Advanced Bash Scripting Guide. Specifically Examples 26-4 and 26-5. Using it as a guide, I think that what you are wanting is ...

Code:

for element in $(seq 0 $((${#stripped_file[@]} - 1 )))
do
 #whatever you want to do using ${stripped_file[$element]}
done

seq will return a sequence of numbers from begin to end. Begin in this case is 0, and end is the number of elements in the $array array minus one. The for loop then assigns each number of that sequence in turn to element.

To change a single element array into a multi-element ...

Code:

new_array=($(echo $old_array))

assuming that $old_array is your single element array.

bryan.out.there · 05-31-2006, 11:44 PM

Thanks for array element assistance Hobbletoe,
Much appreciated. Apologies for late reply but been surfing the sea and not the web for a few days.