regular expressions negation

wakatana · 10-25-2009, 02:04 PM

Hi All,
I am wondering If is possible to write more complcated regexp such this:

lets say I have file

Code:

"datum">Sobota 24. októbra&nbsp;2009

and I want everthing within quotes ("datum") so i write

Code:

grep -oE '"[^"]*"'

which works fine.

And now, what if I want everything that is not in the quotes? (>Sobota 24. októbra 2009)

I tried negation of previous regexp

Code:

grep -oE '[^("[^"]*")]*'

but gives me error:
grep: Unmatched ) or \)

Is possible to write negation of regular expression?

Thank you for reply

tuxdev · 10-25-2009, 02:43 PM

Use the -v flag to inverse grep's results. But, maybe you want to use sed to delete matched text?

wakatana · 10-26-2009, 04:49 AM

Hi,
yes I knew -v option (also with -o is interesting) but was interested if it is possible doing more comlicated regexp, but probably -v is the best solution. Thank you