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Old 06-08-2009, 08:32 AM   #1
0.o
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Regular Expression


I am trying to build a regular expression that will match the following:

http://www.linkedin.com/[a-zA-Z0-9]+
(the above URL followed by anything on the site)

Could someone point me in the right direction?

Thanks!
 
Old 06-08-2009, 08:38 AM   #2
ghostdog74
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show an actual example of the input file you are parsing. basically, there is no need for a regular expression. the general logic can be:
Code:
if "http://" in string
 
Old 06-08-2009, 08:39 AM   #3
pixellany
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What utility are you using? Depending on the context, you may already have it....

You can also use:
http://www.linkedin.com/.*
 
Old 06-09-2009, 02:28 AM   #4
vonbiber
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Quote:
Originally Posted by 0.o View Post
I am trying to build a regular expression that will match the following:

http://www.linkedin.com/[a-zA-Z0-9]+
(the above URL followed by anything on the site)

Could someone point me in the right direction?

Thanks!
you want to get what's after 'http://www.linkedin.com/'?
if you're parsing an html file and you want
to retrieve this info from the hyperlinks found in file.html

sed 's?href=[^ >]*?\n&\n?g' file.html | grep -i 'href=' | \
grep 'http://www\.linkedin\.com' | \
sed 's?^.*http://www\.linkedin\.com/\([^'" \t>]*\).*$?\1?' | \
sort -u

does that answer your question?
 
  


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