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Old 01-22-2009, 10:15 AM   #1
RavenLX
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Registered: Oct 2004
Posts: 88

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Question Regex: How do I put this on one line? (Time-date parsing)


I'm not great at regex so I'll try to explain what I have.

Code:
$line = "Log Created: [12/Dec/2008:06:35:15 -0800] by MyScript on 'ubuntu 8.04 LTS' - - Details: 1/2/3";

$stime = $& if $line =~ /\[.+\]/;
$stime =~ s/^\[//;
$stime =~ s/\]$//;
print "$stime\n";
Would like to put this into $stime in one line instead of 3 so that $stime would have "12/Dec/2008:06:35:15 -0800".

Someone know how to do this?
 
Old 01-22-2009, 10:23 AM   #2
Telemachos
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Registered: May 2007
Distribution: Debian
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If I understand you, and the lines look like your sample does, it's not too bad. Essentially you want to capture everything in between [ and ] and leave the time stuff in the order it's found. This works using Perl:
Code:
#!/usr/bin/perl
use strict;
use warnings;

my $line = "Log Created: [12/Dec/2008:06:35:15 -0800] by MyScript on 'ubuntu 8.04
LTS' - - Details: 1/2/3";

$line =~ m/\[(.+)\]/;
my $stime = $1;

print "$stime\n";
If you have multiple instances of [stuff] on any given line or stretching across lines, things get uglier. The parentheses () put the captured items into numbered scalars ($1, $2, etc.) for use later. Depending on how reliable your output is, it probably pays to check for the existence of $1 before you try to use it.
Code:
my $stime = $1 if $1;

Last edited by Telemachos; 01-22-2009 at 10:25 AM.
 
Old 01-22-2009, 10:56 AM   #3
RavenLX
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Thanks! This works.
 
  


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date, parse, perl, regex, time


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