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The script outputs whatever is returned on line 6, no matter the value of $ARGV[0]. On the other hand, the same function written in Python works perfectly:
It appears that the Perl function is returning as the final value, only what the final iteration of the function returns. Am I missing something about how Perl handles functions and return values?
Perl passes by reference, which is why you need to make local copies of the input values.
Of course, Robhogg is trying to do just that when he assigns to $num. The problem is the word "local": $num is not a local variable. It is a global variable. This problem can be fixed by declaring $num to be a local variable thus, just inside the fact function:
Code:
my $num = $_[0];
An idiom often used, especially if several values are being passed to the function, is this:
I'd stand by my use of the word. Yes, it is by design in Perl (something I'd forgotten), but comparing it to the behaviour of a wide range of other languages (C, C++, Java, Python, bash...) it is a tad quirky.
I'd stand by my use of the word. Yes, it is by design in Perl (something I'd forgotten), but comparing it to the behaviour of a wide range of other languages (C, C++, Java, Python, bash...) it is a tad quirky.
No, it isn't. There are two scoping models implemented in Perl: dynamic and lexical - in that chronological order.
If you insist on the "quirky" word, then C++ is "C" with later added quirks.
Last edited by Sergei Steshenko; 05-29-2010 at 04:08 AM.
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