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orgazmo

06-07-2005 07:09 AM

Read a word in a string with bash

Hi all!!!

Today i've got a new problem.

I'm Trying to extract a word from a string that look like that:

"695856 5859 66:55:66 99:77:55"

In fact i want a command that would allow me to extract, for example, the third word (here 66:55:66)

Thanks

theYinYeti

06-07-2005 07:14 AM

awk seems just right for that, eg:
awk '{print $3}'

Yves.

orgazmo

06-07-2005 07:24 AM

Ok thank you Yves.

but where do i specify the string to be used?

theYinYeti

06-07-2005 07:30 AM

awk reads from standard input or from a file (much like sed). So if your text is in a file, then this will do:

Code:

awk '...' a_file

If your text is produced by other commands, do this:

Code:

other_commands | awk '...'

Finally, if your text is built inside a script, bash will tell you how to "build a custom" standard input. Two most common solutions are:
- Long text:

Code:

awk '...' <<-FIN

Ligne 1 ${objet} coute \$${prix} !

Lighe 2 ...

FIN

- Short text:

Code:

awk '...' <<<"text with ${var} if you want"

Yves.

orgazmo

06-07-2005 07:34 AM

Ok but i can use the pipe (other command | awk ... ) in my script, it makes no difference, does it?

theYinYeti

06-07-2005 09:54 AM

Pipe is OK.

orgazmo

06-07-2005 10:19 AM

thanks, it work just as i excpected!!!

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