LinuxQuestions.org - [SOLVED] Python re.findall inverse Match

Python gods, I ask of you but yet another simplistic question that I hope can be answered. Its better explained showing my code. Here is my list(tmp_pkglist), which contains a list of all Debian (Jessie) packages:
snippet

Code:

 'zssh (1.5c.debian.1-3.2+b1 [s390x], 1.5c.debian.1-3.2 [amd64, arm64, armel, armhf, i386, mips, mipsel, powerpc, ppc64el])',

 'zsync (0.6.2-1)',

 'ztex-bmp (20120314-2)',

 'zurl (1.3.1-4)',

 'zutils (1.3-4)',

 'zutils-dbg (1.3-4) utilities for dealing with compressed files transparently (debug)',

 'zvbi (0.2.35-3) Vertical Blanking Interval (VBI)',

 'zygrib (6.2.3-1)',

 'zygrib-maps (6.2.3-1)',

 'zynadd (1+git.20100609+dfsg0-2)',

 'zynaddsubfx (2.4.3-4)',

 'zynaddsubfx-dbg (2.4.3-4)',

 'zynaddsubfx-dssi (2.4.3-4)',

 'zypper (1.11.13-1)',

 'zypper-common (1.11.13-1) command line software manager using libzypp (common files)',

 'zypper-doc (1.11.13-1) command line software manager using libzypp (documentation)',

 'zziplib-bin (0.13.62-3)',

 'zzuf (0.13.svn20100215-4.1+b1 [s390x], 0.13.svn20100215-4.1 [amd64, arm64, armel, armhf, i386, mips, mipsel, powerpc, ppc64el])']

Using this block of code and using re.findall, how can I tell the regex to "not" or inversely find all of the lines that do not contain:

Code:

 'zssh (1.5c.debian.1-3.2+b1 [s390x], 1.5c.debian.1-3.2 [amd64, arm64, armel, armhf, i386, mips, mipsel, powerpc, ppc64el])

'zzuf (0.13.svn20100215-4.1+b1 [s390x], 0.13.svn20100215-4.1 [amd64, arm64, armel, armhf, i386, mips, mipsel, powerpc, ppc64el])']

I tried various combos but cannot get the inverse of what I want which is:

Code:

 'zypper (1.11.13-1)',

 'zypper-common (1.11.13-1) command line software manager using libzypp (common files)',

 'zypper-doc (1.11.13-1) command line software manager using libzypp (documentation)',

 'zziplib-bin (0.13.62-3)',

For example:

Code:

for scrape in tmp_pkglist:

            capture = re.findall('?!(.*\[s390x\].*))', scrape)

            if capture:

                    print capture

I am used to using "!" or boolean "not" but have never done it using Pythons "re" module. Thanks in advance.