Python Parse Code

snowman81 · 01-23-2009, 09:27 PM

I tried ot take a full program and pare it down to a function within a program and I am sure something is wrong. Actually, since I am getting an error I know something is wrong. Here is the code:

Code:

import re, urllib2, sys, BaseHTTPServer


def getip():
	web_handle = urllib2.urlopen(address)
        

	address = parseAddress(sys.argv[1])
	website_handle = retrieveWebPage(address)
	website_text = website_handle.read()



	foo = re.compile("(\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}\:\d{1,4})")
	bar = website_text
	ip = foo.findall(bar)
for finds in ip:
	return finds

print finds

And this is the error I am getting

Code:

File "parse_example_try1", line 18
   return finds
SyntaxError: 'return' outside function

If it is totally screwed up then I will have to try something different.

CroMagnon · 01-24-2009, 01:29 AM

The error explains it pretty well. You are using 'return' outside a function definition, which is pretty meaningless - return to where?

You probably want something more like this at the end:

Code:

    return foo.findall(bar)

for ip in getip():
    print ip

bgeddy · 01-24-2009, 07:31 AM

Hi snowman81 - please don't take offense but I really think you should look up a basic python tutorial to get to grips with the syntax of the language. You'll always have problems blindly hacking at code without knowing it's structure.

There are loads of good works on line. Just Google "python tutorial". A good introductory one is "A Byte of Python" or "Dive into Python" which is a bit more advanced.

snowman81 · 01-24-2009, 10:50 AM

Meh, no offense taken. I am reading up on it but I think I'm a little impatient and am biting off more than I can chew this early in my learning process.