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Old 08-18-2005, 11:35 AM   #1
shanenin
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Registered: Aug 2003
Location: Rochester, MN, U.S.A
Distribution: Gentoo
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python exception like structure with a timer


I have a program that depends on being able to query a online database. If the internet connection fails, I want the program to continue, but with different parameters. I am currently using an exception like the following:
Code:
try: 
        (query_status, query_info) = CDDB.query(disc_id) 
        results = cd_info(query_status, query_info, disc_id)
        
except:
        do something here
this above method works, but unsatisfactory. The problem is I need to wait for over a minute, maybe two for it ito time out.

Is there a method I could use, to place my two lines of code, like an exception. The result would be if the commands did not finish executing in a set amount of time(say 20 seconds). a secondary clause would execute.

for example:
Code:
try:
        (query_status, query_info) = CDDB.query(disc_id) 
        results = cd_info(query_status, query_info, disc_id)
if not finished in 20 seconds:
        execute this clause

Last edited by shanenin; 08-18-2005 at 11:38 AM.
 
Old 08-18-2005, 11:39 AM   #2
davholla
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Registered: Jun 2003
Location: London
Distribution: Linux Mint 13 Maya
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How about :-

import time
x = time.time()
#your code here
y = time.time()
if y > (x+20):
do a
else:
do b


I have not tested this but I think it should work. Let me know.
 
Old 08-18-2005, 12:49 PM   #3
Crashed_Again
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Registered: Dec 2002
Location: Atlantic City, NJ
Distribution: Ubuntu & Arch
Posts: 3,503

Rep: Reputation: 57
Quote:
Originally posted by davholla
How about :-

import time
x = time.time()
#your code here
y = time.time()
if y > (x+20):
do a
else:
do b


I have not tested this but I think it should work. Let me know.
Yeah even better is:

Code:
import time
time.sleep(60)
Which sleeps 60 seconds.
 
Old 08-18-2005, 01:24 PM   #4
Hko
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Registered: Aug 2002
Location: Groningen, The Netherlands
Distribution: Debian
Posts: 2,536

Rep: Reputation: 111Reputation: 111
Quote:
Originally posted by davholla
How about :-

import time
x = time.time()
#your code here
y = time.time()
if y > (x+20):
do a
else:
do b
That will not do the trick: The call to CDDB.query() will take 1 or 2 minutes. Your code only measures the time it took afterwards.

I think the question was how to make the call to CDDB.query() take less time in case the connection fails.

@shanenin
I don't know about the CDDB-module, but did you look for some way in that module to specify the time-out? That would be the prefferred solution of course. If there's no such way, this might help:

Code:
#!/usr/bin/env python

import time
import signal

# Signal hander function.
# Makes an Exception occur.
def alarmHandler(signalNumber, stackFrame):
	raise IOError, "Time-out"

# Setting handler function.
# The handler will be run when a SIGALARM
# interrupts the program
signal.signal(signal.SIGALRM, alarmHandler)

# Setting the shorter time-out here: 5 secs.
# This will interrupt the program after 5 secs
# from now.
# Comment out the line below to simulate normal
# time-out or successful query.
signal.alarm(5)

try:
	# Simulate a query timing out in 1 minute.
	print "Start (simulated) query time-out"
	time.sleep(60)  # Put your query-call here instead.
except IOError:
	print "Time out! " * 5

print "Finished"

Last edited by Hko; 08-18-2005 at 01:49 PM.
 
Old 08-20-2005, 10:44 AM   #5
shanenin
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Registered: Aug 2003
Location: Rochester, MN, U.S.A
Distribution: Gentoo
Posts: 987

Original Poster
Rep: Reputation: 30
That last code worked, thanks. :-)
 
  


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