Hi All,

I am trying to create a sed script that will locate text at the beginning of a line (MOZ_ARCH=$(uname -m)); insert a comment at the beginning of the line (#MOZ_ARCH=$(uname -m); and then append the line with (MOZ_ARCH=$(i686)

The OS is x86_64 RHEL5 Workstation using the input file /usr/bin/firefox.

Here is my script and the output:

[root@cels159075 bin]# sed 's/MOZ_ARCH=/#MOZ_ARCH/' /usr/bin/firefox | grep \#MOZ_ARCH

#MOZ_ARCH$(uname -m)

As you can see this is part of what I"m trying to accomplish, but I don't know how to append the line with MOZ_ARCH=$(i686)

Any help would be very appreciated.

Thanks

You can try to substitute the entire line with two lines, including a newline character in the replacement string:
or append a line with the 'a' command after the matching pattern:

sed 's/^MOZ_ARCH=.*/#& MOZ_ARCH=$(i686)/' /usr/bin/firefox

But I can't tell what you really want. Do you want to change the value after MOZ_ARCH= or add another MOZ_ARCH entry?
Please post the actual line and how you want it to change.

Or do you want to add MOZ_ARCH=$(i686) on the next line?
Without the -i option the file isn't actually changed but just displayed. Either redirect the file to a temp file and then replace the current file or use the -i option. I'd recommend not using -i until after you are sure the sed command does what you want. Also backup the original just in case.

Hi All,

Thanks for the quick response and all of your suggestions. Colucix's suggestion was exactly what I was looking for.

sed 's/MOZ_ARCH=$(uname -m)/#MOZ_ARCH=$(uname -m)\nMOZ_ARCH=$(i686)/' file

Thanks