Hi, I'm trying to make a script that reads from a file, if the words "ADD" occures the function AddName should be called with the name that follows as an argument

The problem is that awk cuts away the newline or something like that. Why?? Can someone help me?


# This is the file i read from
Blablabla;test
ADD;Tom
blabla;ok
ADD;Mark


# This is the script
function AddName()
{
echo "Added"
}
temp=`awk -F";" '
{
if ( $0 ~/^'"#"'/ )
{
# Ignore "#"
}
else
{
if ( $1 == "ADD" )
{
print "AddName "$2
}
fi
}' file`
$temp
exit 0

The output if I echo it would be:
AddName Tom AddName Mark

I want it to be:
AddName Tom
AddName Mark

I think you just need to add \n to the end of the
print "AddName "$2
line to read:
print "AddName "$2\n

Don't have a linux box to test on right now, so this is off the top of my head.

Nope, that just returned the error: "backslash not last character on line"

I also tried:
print "AddName "$2"\n"
printf "AddName "$2
printf "AddName "$2\n
printf "AddName "$2"\n"

\n seems to output a <space>
now i have tried with \f and \r as well. With \f\r it came on seperate lines when i echoed it, but it would not run, I think because in "reality" it is still on one line.. Any other suggestions?

I read something about ORS(Output record seperator), and tried this

ORS="\n"
print "AddName "$2

but i did not help.

I,m stuck here, can someone help please???

Uhh... have you tried: print "AddName $2\n" ?

I have now, but that didn't do the trick... same output.

I got help somewhere else...
The solution if someone wonders:
function AddName()
{
echo "Added"
}
temp=`awk -F";" '
{
if ( $0 ~/^'"#"'/ )
{
# Ignore "#"
}
else
{
if ( $1 == "ADD" )
{
print "AddName "$2
}
fi
}' file`

OLDIFS="$IFS"
IFS=$'\n'
for command in $temp; do
$command
done
IFS="$OLDIFS"
exit 0