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Old 02-23-2010, 10:36 AM   #1
shifter
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problem with return function value in perl

$val = mkdir $directory, 755
print $val;

does't create directory but return as value '0'

$val = 0 means true o false?
 
Old 02-23-2010, 10:52 AM   #2
smoker
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should be
Code:
$val = mkdir $directory, 0755;
assuming $directory is defined beforehand.

true = 1
 
Old 02-23-2010, 10:04 PM   #3
chrism01
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I'd use this
Code:
mkdir($directory, 0755) or die "mkdir failed: msg was $!\n";
http://perldoc.perl.org/functions/mkdir.html
 
  


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