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Old 04-24-2009, 04:10 PM   #1
Registered: Apr 2009
Location: Boston MA
Distribution: CentOS 6.2 x86_64 GNU/Linux
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Print only specific rows in a text file

Hi there,
thanks for your help with my questions yesterday!

I have a simple one now, I guess. Yet, getting a solution through Google with key words such as "awk, print, rows" seemed hard.

Here is my question:

I have a text file with 100 rows. I want to make "new_file1.txt" containing rows 1-10, "newfile_2.txt" containing rows 11-20, etc.

(By the way, each row contains a long string of characters, so there's not a clear column structure)

Thanks in advance,


Last edited by Mike_V; 04-24-2009 at 04:25 PM.
Old 04-24-2009, 05:07 PM   #2
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Hi -

To print lines 1 through 10 (for example):
sed '1,10!d' INFILE > OUTFILE
'Hope that helps .. PSM

Here's a great sed "cheat sheet":
Old 04-24-2009, 05:33 PM   #3
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The split program is written for exactly this task:
split --lines=10 --numeric-suffixes oldfile.txt newfile_

# if you want .txt extension
for f in newfile_* ; do
    mv $f $f.txt
Old 04-24-2009, 07:18 PM   #4
Registered: Apr 2009
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You guys are awesome!


awk, print

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