Print only specific rows in a text file

Mike_V · 04-24-2009, 04:10 PM

Hi there,
thanks for your help with my questions yesterday!

I have a simple one now, I guess. Yet, getting a solution through Google with key words such as "awk, print, rows" seemed hard.

Here is my question:

I have a text file with 100 rows. I want to make "new_file1.txt" containing rows 1-10, "newfile_2.txt" containing rows 11-20, etc.

(By the way, each row contains a long string of characters, so there's not a clear column structure)

Thanks in advance,

Cheers,
Mike

paulsm4 · 04-24-2009, 05:07 PM

Hi -

To print lines 1 through 10 (for example):

Quote:

sed '1,10!d' INFILE > OUTFILE

'Hope that helps .. PSM

PS:
Here's a great sed "cheat sheet":
http://student.northpark.edu/pemente/sed/sed1line.txt

ntubski · 04-24-2009, 05:33 PM

The split program is written for exactly this task:

Code:

split --lines=10 --numeric-suffixes oldfile.txt newfile_

# if you want .txt extension
for f in newfile_* ; do
    mv $f $f.txt
done

Mike_V · 04-24-2009, 07:18 PM

You guys are awesome!