pointer to structure

Xiangbuilder · 10-09-2003, 01:23 AM

I have two questions about the program that is at the bottom of the post:
First, if I write a program

Code:

int* ip=&i;

then I can use

Code:

cout<<ip;

to output the address of i; similar to this, can I output the address of s1.c by the command that contains the words sp1? I ask this because I have written

Code:

structure3* sp1=&s1;

Second, is the address of s1.c really aB? Why is not some value as 0x... as the address of s1.i?

Code:

#include<iostream>
using namespace std;

typedef struct struct3 {
   char c;
   int i;
} structure3;
int main ()
{
   structure3 s1, s2;
   structure3* sp1=&s1;
   structure3* sp2=&s2;
   s1.c='a';
   s1.i=1;
   sp2->c='b';
   sp2->i=2;
   
   cout<<"sp1->c="<<sp1->c<<endl
       <<"sp1->i="<<sp1->i<<endl;
   cout<<"s2.c="<<s2.c<<endl
       <<"s2.i="<<s2.i<<endl;
   cout<<"&s1.c="<<&s1.c<<endl
       <<"&s1.i="<<&s1.i<<endl;
}

[root@localhost a_pointers]# ./simple_struct3_c
sp1->c=a
sp1->i=1
s2.c=b
s2.i=2
&s1.c=a
B
&s1.i=0xbfffda44
[root@localhost a_pointers]#

Thank you.

dimm_coder · 10-09-2003, 02:00 AM

Quote:

Originally posted by Xiangbuilder
cout<<"&s1.c="<<&s1.c<<endl
}
[root@localhost a_pointers]#[/code]Thank you. [/B]

c is a char, so &s1.c is interpreted like char* and cout think that it has to write a string (char*) and it so this.

int * a = new int;
cout << a << endl; // put the address of a (int*)

char * s = "i'm a string";
cout << s << endl; // put a string, not the address of s;

So if U want to get the address,
U need to write cout << (int*)(&s1.c) << endl;

Xiangbuilder · 10-09-2003, 03:39 AM

Thank you.
I feel I can understand some parts of your post,
and I can't understand others because of my poor c++ knowledge.
Howeve, I have downloaded it for future learning.
Thank you.