LinuxQuestions.org - plz help me to compare

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plz help me to compare

Dear all
I want to compare the zones in both my Linux Bind servers, So I greped the first line of all of them with
#> grep 'zone "' named.conf > named.1
and the same for named.conf 2
now I get two files named.1 named.2, with the following syntax
zone "domain1.com" in {
zone "domain2.com" in {
zone "domain3.cc" in {
zone "domain4.net" in {
zone "domain5.tv" in {
etc..

First Can any one tell me a grep command to just get the domains name between the "" in a file
second I want to compare between the both files and get the domains that in named.1 and not found in named.2

Not tested:

Code:

egrep -o '"[^"]+"' file1 | sed 's/"//g'  > comp1

egrep -o '"[^"]+"' file2 | sed 's/"//g' > comp2

sdiff -s comp1 comp2

Cheers,
Tink

Thanx so much
the first command worked perfectly
But there's something in the second one
It compared with two files as they are arranged like each others, But they don't
For example name1
zone "domain1.com" in {
zone "domain2.com" in {
zone "domain3.cc" in {
zone "domain4.net" in {
zone "domain5.tv" in {
etc..

But named2
zone "domain5.tv" in {
zone "domain3.cc" in {
zone "domain2.com" in {
zone "domain4.net" in {
zone "domain1.com" in {
etc..

I just want it to get the domains that are in one of them and not in the other, To add it to the other one, Got it.

Thanx for your help.

Quote:

Originally Posted by reaky

I just want it to get the domains that are in one of them and not in the other, To add it to the other one, Got it.

how about:

Code:

$ cat name1 name2 |sort |uniq > allnames

$ cat allnames

zone "domain1.com" in {

zone "domain2.com" in {

zone "domain3.cc" in {

zone "domain4.net" in {

zone "domain5.tv" in {

Of course, if the original order is important to you this might not be so great...

Code:

egrep -o '"[^"]+"' file1 | sed 's/"//g' | sort  > comp1

egrep -o '"[^"]+"' file2 | sed 's/"//g' | sort  > comp2

sdiff -s --left-column comp1 comp2

sdiff -s --left-column comp2 comp1

How's that?

Cheers,
Tink

No I don't want to arrange them, I just want to compare.
Thanx for help

I recently had to prepare scripts that extracted the names of mpeg files in several video devices against one of the devices. I used the "comm" command to find entries in one list that were unique, and then used that list as a grep pattern file to the original.

Code:

$ cat rdytospot

#!/bin/bash

for file in *.RDY; do

  sed -e '0,/Unmanaged/d' -e '/NETTEST/d' -e '/^$/,$d' -e '/^$/d' -e 's/\(.*MPG\).*/\1/' -e 's/[[:blank:]]//g' "$file"

done > unmanagedspots

sort -u unmanagedspots >unmsorted

comm -23 unmsorted solicitorlist >deletelist

if grep -f deletelist solicitorlist; then

  echo Error!  The delete list contains files in the solicitor

  exit 1

fi

sed 's/^/del /' deletelist >clean.dvc

rm unmanagedspots unmsorted deletelist

You could do something similar:

Code:



sed -n '/^zone/s/^[^"]*"\([^"]*\)".*/\1/p' named2 | sort >named2list

sed -n '/^zone/s/^[^"]*"\([^"]*\)".*/\1/p' named1 | sort >named1list

comm -13 named1list named2list >UniqInNamed2

grep -f UniqInNamed2 named2

By the way, your two samples have exactly the same domain names, just in a different order.
Using different samples:
$ cat named1
zone "domain1.com" in {
zone "domain2.com" in {
zone "domain3.cc" in {
zone "domain4.net" in {
zone "domain5.tv" in {

$ cat named2
zone "domain8.tv" in {
zone "domain3.cc" in {
zone "domain7.com" in {
zone "domain4.net" in {
zone "domain1.com" in {

$ grep -f UniqInNamed2 named2
zone "domain8.tv" in {
zone "domain7.com" in {

Quote:

Originally Posted by reaky

No I don't want to arrange them, I just want to compare.
Thanx for help

Sorry mate, w/o sorting the diff output will be
garbage. With the sorting you get two sets that
(most likely) won't appear in either, and then
you could feed them back. If that's not what
you're after *I* can't help you.

Cheers,
Tink

try this:

Code:

# system 1

grep '^zone "' named.conf | awk '{print $2}' | tr -s '"' ' ' > file1

# system 2

grep '^zone "' named.conf | awk '{print $2}' | tr -s '"' ' ' > file2

awk ' FILENAME=="file1" { arr[$0]=1}

      FILENAME=="file2" {

          if( !arr[$0]) { print $0 }

      }

    ' file1 file2

Dear all
Thanx so much ,You really helped me so much
THax all again. :)