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batman4 02-05-2013 12:25 AM

Please explain a example from knr book
 
I am going through this book and i m getting confused with one program which i am copy/pasting below .

Code:

#include <stdio.h>

int power(int m, int n);

/* test power function */
main()
{
int i;
for (i = 0; i < 10; ++i)
printf("%d %d %d\n", i, power(2,i), power(-3,i));
return 0;
}
/* power: raise base to n-th power; n >= 0 */
int power(int base, int n)
{
int i, p;
p = 1;
for (i = 1; i <= n; ++i)
p = p * base;
return p;
}

algorithm waht i have understood is:
for i =0
then power function is called power(2,0) =1

then i=1
power(2,1)=2

then i=2
in power(2,2)
first p(2,1) =2
second p(2,2) =4

then i=3
int power(2,3)
first p(2,1) =2
second p(2,2) =4
third p(2,3)=8

it should print for each case .
and by doing this it should generate duplicate copies but it is not happening .
Please explain the reason for same.

pan64 02-05-2013 12:46 AM

sorry guy, it should generate duplicate copies of what? Please explain what do you expect!

rigor 02-05-2013 02:12 AM

Hi batman4!

It's been many years since I had a copy of K&R around. So unfortunately, I can't just look up the example.

As has been mentioned by pan64, from what you've said, it doesn't seem entirely clear, what you're expecting, especially when compared to the code you've shown us.

I'm hoping that the most important thing to you, is to get output similar to what you've shown is. So I've included here, code modified to produce output somewhat like what you've shown us. Even then, the output that you've shown us, doesn't appear to me, to be entirely consistent even with itself. But I hope that what I've shown you here, helps you understand the problem better.

Here's the code after I modified it:

Code:

#include <stdio.h>


int power(int m, int n) ;


/* test power function */
main()
{
    int i ;


    for (i = 0 ; i < 10 ; ++i)
    {
        printf(  "\ni=%d:\n" ,  i  ) ;
        power( 2 ,  i  ) ;
    }

    return 0 ;
}


/* power: raise base to n-th power ; n >= 0 */
int power(  int base ,  int n  )
{
    int i ,  p ;


    p = 1 ;

    printf(  "power(%d,0)=%d\n" ,  base ,  p  ) ;

    for (  i = 1 ;  i <= n ; ++i  )
    {
        p = p * base ;
        printf(  "power(%d,%d)=%d\n" ,  base ,  i ,  p  ) ;
    }

    return p ;
}

When I run the program above, it produces the following output:

Code:

                                                                                                                                                                                                                                                                     
i=0:
power(2,0)=1

i=1:
power(2,0)=1
power(2,1)=2

i=2:                                                                                                                                                                                                                                                                 
power(2,0)=1
power(2,1)=2
power(2,2)=4

i=3:
power(2,0)=1
power(2,1)=2
power(2,2)=4
power(2,3)=8

i=4:
power(2,0)=1
power(2,1)=2
power(2,2)=4
power(2,3)=8
power(2,4)=16

i=5:
power(2,0)=1
power(2,1)=2
power(2,2)=4
power(2,3)=8
power(2,4)=16
power(2,5)=32

i=6:
power(2,0)=1
power(2,1)=2
power(2,2)=4
power(2,3)=8
power(2,4)=16
power(2,5)=32
power(2,6)=64

i=7:
power(2,0)=1
power(2,1)=2
power(2,2)=4
power(2,3)=8
power(2,4)=16
power(2,5)=32
power(2,6)=64
power(2,7)=128

i=8:
power(2,0)=1
power(2,1)=2
power(2,2)=4
power(2,3)=8
power(2,4)=16
power(2,5)=32
power(2,6)=64
power(2,7)=128
power(2,8)=256

i=9:
power(2,0)=1
power(2,1)=2
power(2,2)=4
power(2,3)=8
power(2,4)=16
power(2,5)=32
power(2,6)=64
power(2,7)=128
power(2,8)=256
power(2,9)=512


PrinceCruise 02-05-2013 05:14 AM

Quote:

Originally Posted by batman4 (Post 4884571)
it should print for each case .
and by doing this it should generate duplicate copies but it is not happening .
Please explain the reason for same.

I probably understand why you believe that main should print every time from the power(2,0), it's because the confusing return statement and the for loop in function power().
Now look at this way with proper quotes:-

Quote:

for (i = 1; i <= n; ++i)
{
p = p * base;
}
return p;
It returns the final value after completing the whole loop.

PS : Learning gdb to debug C codes will be a good idea. Lots of things get clear. :)

Regards.


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