[SOLVED] PHP parse error unexpected '>'

PradeepRahul · 12-28-2011, 09:48 AM

<?php
$hostname = "localhost";
$user = "root";
$password = "";
$database = "customer";
$conn = mysql_connect($hostname,$user,$password) or die("Connection Not Found");
mysql_select_db($database);
$sql = mysql_query("SELECT * FROM a);
while($result = mysql_fetch_array($sql)) {
echo " Name = " .$result["name"] . " ";
echo " Age = " .$result["nick"] . " ---------------- ";
}
?>

---------- Post added 12-28-11 at 09:19 PM ----------

Please somebody help me quick

JimBrewster · 12-28-2011, 10:26 AM

Quote:

Originally Posted by PradeepRahul

<?php
$hostname = "localhost";
$user = "root";
$password = "";
$database = "customer";
$conn = mysql_connect($hostname,$user,$password) or die("Connection Not Found");
mysql_select_db($database);
$sql = mysql_query("SELECT * FROM a);
while($result = mysql_fetch_array($sql)) {
echo " Name = " .$result["name"] . " ";
echo " Age = " .$result["nick"] . " ---------------- ";
}
?>

---------- Post added 12-28-11 at 09:19 PM ----------

Please somebody help me quick

Without trying it out or looking it up, I'd guess that '.$result[foo]' in lines 10 & 11 won't parse as a concatenation without a space after the '.'

Cedrik · 12-28-2011, 11:11 AM

Missing matching quote in $sql = mysql_query("SELECT * FROM a);

(using text editor with colored syntax may help)

PradeepRahul · 12-29-2011, 05:28 AM

Thanks alot for your reply!!