PHP "for.. loop" to insert into mysql

Boby · 05-28-2004, 07:24 AM

hello!

i want to create a homepage on my LAN. i have the fotogallery saved on the web.
there are many pictures with thumbnails. i want to save all the links in a mysql database. i would like to write a script that aumatticaly writes them to the database so don't have to copy>>paste about 200 links to a manually insert.

the pictures are saved like this:

pictures are here:
www.homepage.com/gallery/holiday/pic01.jpg
.......
www.homepage.com/gallery/holiday/pic10.jpg
.......
www.homepage.com/gallery/holiday/pic50.jpg

for each picture i have 2 thumbnails:

www.homepage.com/gallery/holiday/pic01_t.jpg
.......
www.homepage.com/gallery/holiday/pic50_t.jpg

and

www.homepage.com/gallery/holiday/pic01_t1.jpg
.......
www.homepage.com/gallery/holiday/pic01.t50jpg

ok..i created a database that should look like the screenshot that i attached.
this is the screenshot of my wannabe table: http://www.frozenminds.de/table_example.png

this is the php code that i wrote...but it doesn't write anything to my database. maybe you could help me, 'cause i'm a real

Code:

<?

$db_host = "localhost";
$db_username = "boby";
$db_password = "********";
$db_name = "mydatabase";

mysql_connect($db_host,$db_username,$db_password) or die(mysql_error());
mysql_select_db($db_name) or die(mysql_error());

for ($i = 1; $i <= 50; $i++)
{
$pic = 'www.homepage.com/gallery/schaessburg/pic'.$i.'';
$thumb1 = 'www.homepage.com/gallery/schaessburg/pic'.$i.'t';
$thumb2 = 'www.homepage.com/gallery/schaessburg/pic'.$i.'t'.$i.'';
$gallery = 'holiday';
$query = "INSERT INTO foto (picture, thumb1, thumb2, gallery)
VALUES ('$pic','$thumb1',$thumb2','$gallery')";
mysql_query($query);
}
mysql_close();

?>

could anyone help me?
thanx a lot!

cheers, boby

flakzeus · 05-28-2004, 07:40 AM

I see a couple of things wrong here, first you have start a php script with <?php and not just <?. Second, to use mysql_select_db() you have to give it a connection to select the database on, for example: mysql_select_db($db_name, $connection); so by putting the mysql_connect into a variable it allows you to pass that connection to select_db and any other connection you may need later.

PHP Code:


			
<?php



$db_host = "localhost";

$db_username = "boby";

$db_password = "********";

$db_name = "mydatabase";

$connection = mysql_connect($db_host,$db_username,$db_password) or die(mysql_error());

$databse = mysql_select_db($db_name, $connection) or die(mysql_error());



for ($i = 1; $i <= 50; $i++)

{

$pic = 'www.homepage.com/gallery/schaessburg/pic'.$i.'';

$thumb1 = 'www.homepage.com/gallery/schaessburg/pic'.$i.'t';

$thumb2 = 'www.homepage.com/gallery/schaessburg/pic'.$i.'t'.$i.'';

$gallery = 'holiday';

$query = "INSERT INTO `foto` (picture, thumb1, thumb2, gallery)VALUES ('$pic','$thumb1',$thumb2','$gallery')";

mysql_query($query, $connection);

}

mysql_close();

?>

That's just a couple of things that jump out at me. Try that and see what happens, I don't have much time right now.

Boby · 05-28-2004, 09:06 AM

hhmmm...still no entries

i really don't know where's the point. i get no errors but no entries too.

flakzeus, if you have later some time for this, or somebody else, could you just try something else out? maybe another script. i tried youre script, then i tried to modify it, but it's still not working.

thank you!

keefaz · 05-28-2004, 09:29 AM

The screenshot link is actually empty but the script from flakzeus should add entries to the table foto (the '.jpg' extension misses but anyway the strings should be here in the fields). You did not get any error output from the query ?

Boby · 05-28-2004, 09:38 AM

i get no errors, that's why i don't know where to search for problem. i get an white, empty page.
is there maybe a mysql or linux shell script that could help me out?

ok...i fixed the link to the screenshot...i didn't wrote it correctly, sorry!
here it is: http://www.frozenminds.de/table_example.png

i'll put the same wannabe table that should be generated by the script in this thread.
here it is:

Code:

+----+-------------------------------+---------------------------------+-----------------------------------+---------+
| id | picture                       | thumb1                          | thumb2                            | gallery |
+----+-------------------------------+---------------------------------+-----------------------------------+---------+
|  1 | www.home.../holiday/pic01.jpg | www.home.../holiday/pic01_t.jpg | www.home.../holiday/pic01_t1.jpg  | holiday |
|  2 | www.home.../holiday/...       | www.home.../holiday/...         | www.home.../holiday/...           | holiday |
|  3 | www.home.../holiday/pic50.jpg | www.home.../holiday/pic50_t.jpg | www.home.../holiday/pic50_t50.jpg | holiday |
+----+-------------------------------+---------------------------------+-----------------------------------+---------+

thanX

keefaz · 05-28-2004, 11:06 AM

Maybe a tip : try to play with the quote (`) in the query. For my part I use quote only for field value and the entire query in double quote.
[php]
$query = "INSERT INTO foto (picture, thumb1, thumb2, gallery) VALUES ('$pic','$thumb1',$thumb2','$gallery')";

towlie · 05-28-2004, 12:19 PM

don't know if anyone noticed this or not, but in these code samples, $thumb2 has a single quote only after it, but not before it, (it should be '$thumb2').

when you say you're not getting errors, which errors are you talking about? the ones from the apache error log?

i use php/mysql myself, and the apache error log gives you all of the php errors with filenames and line numbers the errors occured on, making debugging a file much easier.

if you don't know where it is, i'm on slack 9.1, and mine is /var/log/apache/error_log, if i remember correctly.

keefaz · 05-28-2004, 12:23 PM

You right towlie I did not noticed that

and also run slackware 9.1 here, same error_log for apache. In slackware php package php.ini is configured to not show error but log them in /var/log/apache/error_log

flakzeus · 05-28-2004, 01:02 PM

One reason you are getting a blank screen is because your not telling it to print anything. Try this and see if you get errors.

PHP Code:


			
<?php

$db_host = "localhost";
$db_username = "boby";
$db_password = "********";
$db_name = "mydatabase";
$connection = mysql_connect($db_host,$db_username,$db_password) or die(mysql_error());
$databse = mysql_select_db($db_name, $connection) or die(mysql_error());

for ($i = 1; $i <= 50; $i++)
{
$pic = 'www.homepage.com/gallery/schaessburg/pic'.$i.'.jpg';
$thumb1 = 'www.homepage.com/gallery/schaessburg/pic'.$i.'t.jpg';
$thumb2 = 'www.homepage.com/gallery/schaessburg/pic'.$i.'t'.$i.'.jpg';
$gallery = 'holiday';
$query = "INSERT INTO `foto` (picture, thumb1, thumb2, gallery)VALUES ('$pic','$thumb1','$thumb2','$gallery')";
$result = mysql_query($query, $connection);
}
    if ($result != FALSE)
        {
        print "Query was successful <br>";
    }
        else
        {
        print "Query was unsuccessful <br>";
        print "<br>";
        print mysql_errno($connection) . ": " . mysql_error($connection) . "\n";
    }

mysql_close();
?>

keefaz · 05-28-2004, 03:26 PM

yes and don't forget the .jpg extension

PHP Code:


			
/* for number like 01, 02, 03... */

$picNumber = sprintf("%02d", $i);



$pic = "www.homepage.com/gallery/schaessburg/pic$picNumber.jpg";

$thumb1 = "www.homepage.com/gallery/schaessburg/pic$picNumber"."_t.jpg";

$thumb2 = "www.homepage.com/gallery/schaessburg/pic$picNumber"."_t$i.jpg";

Boby · 05-29-2004, 10:07 AM

hey it's working... thanX a lot guys!!

cheers, boby