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Old 02-09-2013, 04:58 PM   #1
sunil9009
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perl regex


hi guys, i am trying to grab just the fqdn ( with domainname as xyz.com) from the file with the following contents.

Quote:
AAA-BBB-CCC aaa-bbb-ccc-2345.xyz.com aa-dg-hj hira.xyz.com
ddd-eee-fff-4567.xyz.com ddd-eee-fff vffg.xyz
sunil.xyz.com mad.xyz.com
eg: Expected output

Quote:
aaa-bbb-ccc-2345.xyz.com
hira.xyz.com
ddd-eee-fff-4567.xyz.com
sunil.xyz.com
mad.xyz.com
I tried the following code, but it resolves partially.

Quote:
while (<>) {
m/\s*(.*?\.xyz.com)/;
print "$1 \n";
}
Any help would be greatly appreciated
 
Old 02-09-2013, 06:24 PM   #2
sag47
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I don't know about perl but this can be solved with tr and grep.

Code:
cat /somefile | tr ' ' '\n' | grep 'xyz\.com$'

Last edited by sag47; 02-09-2013 at 06:26 PM.
 
Old 02-10-2013, 05:15 AM   #3
grail
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I am not sure with perl as you need some way to revisit the same line, but in ruby it would look like:
Code:
ruby -ne '$_.scan(/[^.\s]+\.xyz\.com/).each{|x| puts x}' file
Hopefully this might help lead you to a perl solution

This does show that your original solution obviously won't work from the fact that you would need to print not only $1 on some lines.

Last edited by grail; 02-10-2013 at 05:16 AM.
 
Old 02-11-2013, 07:00 AM   #4
mina86
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http://stackoverflow.com/questions/7...ugh-each-match
 
  


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