LinuxQuestions.org - [SOLVED] Pass space (or string escaped) as argument to shell script.

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Pass space (or string escaped) as argument to shell script.

Hello, i need to pass a message to my Java, I use a shell script tu set all the environment.

I use this code inside the script:

Code:

java -cp $CP App $1 $2

But when i try to run the script and pass a string like this:

Code:

./AppShell SndMsg "Wellcome to my app"

"Wellcome to my app" is send as 4 differente arguments.

This happend to if I use:

Code:

./AppShell SndMsg "Wellcome\ to\ my\ app"

Code:

./AppShell SndMsg Wellcome\ to\ my\ app

How can i pass the second parameter as complete string to my shell and then passed to my java app.

Solved, sorry the way is pass the shell variable between quotes, like this:

Code:

java -cp $CP App $1 "$2"

and launch the script this way:

Code:

./AppShell SndMsg "Wellcome to my app"