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Old 06-22-2004, 05:01 AM   #1
Registered: Mar 2004
Posts: 79

Rep: Reputation: 15
Question "No matching Call Error"

Following code is giving compilation error in g++.

using namespace std;

template<typename T>
struct subvector_traits
typedef T* iterator;

template<typename T>
class subvector

typedef typename subvector_traits<T>::iterator iterator;
void initialize(iterator start,iterator end)

iterator m_pstart;
iterator m_pend;

int main()
subvector<unsigned int> cells;
static vector<unsigned int> m_nMembercells;
return 0;

Error Message:- >

no matching function for call to `subvector<unsigned int>::
initialize(__gnu_cxx::__normal_iterator<unsigned int*, std::vector<unsigned
int, std::allocator<unsigned int> > >, __gnu_cxx::__normal_iterator<unsigned
int*, std::vector<unsigned int, std::allocator<unsigned int> > >)'
initialize.cpp:20: candidates are: void
subvector_traits<T>::iterator) [with T = unsigned int]
initialize.cpp:37:2: warning: no newline at end of file

If anyone has some idea then please help
Thanx in advance
Old 06-23-2004, 02:37 PM   #2
Registered: Aug 2002
Distribution: Debian
Posts: 540

Rep: Reputation: 32
That is some sweet code... sweetly broken that is. I am still learning C++, but I can tell you some things:
(1): I don't know what your doing with those typedefs, but it isn't healthy.
(2): struct subvector_traits is an empty stucture.
(3 The usual reason the comiler would be giving that error is because you need to do some type-casting.

Basically I am no help, so you shouldn't listen to me!


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