need help in scripting.....

raghuvamsi · 06-27-2008, 04:07 AM

hi all
I have to write a script, which will copy data (IP addresses) from IP_ADDRS file to different files (one IP address will be copped to one file).

IP_ADDRS file

IP_SYS1=193.168.1.1
IP_SYS2=193.168.1.2
IP_SYS3=193.168.1.3
IP_SYS4=193.168.1.4
IP_SYS5=193.168.1.5
IP_SYS6=193.168.1.6
IP_SYS7=193.168.1.7
IP_SYS8=193.168.1.8

And device details.

--------------------------------

Each address should be copped one file like

IP_SYS1 to sys1.txt

IP_SYS2 to sys2.txt

The sys1.txt should look like

IP_ADDR= 193.168.1.1

The sys2.txt should look like

IP_ADDR= 193.168.1.2

I wrote two scripts do this. But I need to do this with a single script.

please suggest me one procedure to do this using a single script.

Thank you.

colucix · 06-27-2008, 04:49 AM

Can you post the scripts you wrote? Maybe you can easily put them together. Anyway, my personal solution would be

Code:

#!/bin/bash
while read line
do
  file=$(echo ${line%=*} | cut -c 4- | tr '[A-Z]' '[a-z]').txt
  echo "IP_ADDR= ${line#*=}" > $file
done < IP_ADDRS

radoulov · 06-27-2008, 04:59 AM

You could try something like this:

Code:

awk -F'[_=]' '{
  printf "IP_ADDR= %s\n", 
    $3 > tolower($2)".txt"
}' ip_addrs_file

If the ip_addrs_file is too large,
use this:

Code:

awk -F'[_=]' '{
  print f, $2
  close(f)
  printf "IP_ADDR= %s\n", 
    $3 > (f = tolower($2)".txt")
}' ip_addrs_file