Need bash script to list files, drop extension and dump to file

talwar_ · 06-01-2007, 02:39 AM

Hi all,

I'm trying to write an elegant bash script to list files in a specified directory with a particular extension, drop the extension and output to a file.

The directory name should be hard coded within the script, because the script will not reside in that directory.

So lets say my folder contains the following files:

a.todump
b.todump
c.todump
other.ext
other2.ext

The script should dump only files with .todump extension, but must drop the extension. The contents of the dumped file should be:

a
b
c

ive been trying for a little while but been unsuccessful as im not experienced with shell scripts and havent been using linux long enough to know all the useful shell commands. It should be pretty simple though. Thanks in advance for your assistance!

flupke · 06-01-2007, 02:51 AM

This should do the trick :

Code:

#!/bin/sh

DIR="/your/directory/here"
SUFFIX="todump"

for i in "$DIR"/*.$SUFFIX
do
    echo ${i%%.$SUFFIX} |sed 's#^.*/##'
done

HTH
Flupke

talwar_ · 06-01-2007, 03:00 AM

Hey flupke,

thanks for the prompt reply! will test it out when i have a chance

ghostdog74 · 06-01-2007, 03:01 AM

Code:

for file in *todump; do  mv $file ${file%.todump}; done

talwar_ · 06-02-2007, 05:48 AM

ok.. flupke's post works great. ghostdog, i think you misunderstood me as your code is going to rename my files.. thats not i want. only wanted them renamed in the dumped file.

paisal · 11-04-2010, 10:33 PM

Quote:

Originally Posted by flupke

This should do the trick :

Code:

#!/bin/sh

DIR="/your/directory/here"
SUFFIX="todump"

for i in "$DIR"/*.$SUFFIX
do
    echo ${i%%.$SUFFIX} |sed 's#^.*/##'
done

HTH
Flupke

Thank Flupke is work for me

andekoppen · 05-25-2011, 12:53 PM

Hi

I realize that this is properly a "dead" thread but I thought I'd give it a go.

I'm trying to create a script, that's quite similar to the one presented by ghostdog74, but I can't get it to work.

The script is:
#!/bin/bash

NAVN="prescript - "

for i in "$NAVN"*
do
mv $i ${i#NAVN}
done

The difference being that I want to remove the prescript of some files rather than the extension, but when I run it, i get the error:
"mv: the target 'A' is not a catalog "
(The error is in Danish so it might not be the same wording in the English error, but this is the literal translation).

What am I doing wrong?

catkin · 05-25-2011, 02:11 PM

Please start your own thread. It might be helpful to add set -xv to your script to see what it is doing -- or put an echo before the mv.

martaskolda · 06-01-2011, 09:13 AM

Did you say ELEGANT? You don't need loops, just do

Code:

ls *.todump | sed 's/.todump//g'

chrism01 · 06-02-2011, 12:44 AM

There's a couple of nice Linux cmds for separating filenames from dir names:
http://linux.die.net/man/1/basename http://linux.die.net/man/1/dirname
The first will also separate out file extension strings

Reuti · 06-03-2011, 09:18 AM

Quote:

Originally Posted by andekoppen

The script is:
#!/bin/bash

NAVN="prescript - "

for i in "$NAVN"*
do
mv $i ${i#NAVN}
done

Are there real blanks in the filenames like you mention in "prescript - "? Then the mv will also need quotes around each argument, so that they are still seen as one argument despite the multiple blanks which would separate different arguments otherwise.

And you need a second $:

Code:

mv "$i" "${i#$NAVN}"