LinuxQuestions.org - [SOLVED] mkdir naming variable

- Programming (https://www.linuxquestions.org/questions/programming-9/)

- - mkdir naming variable (https://www.linuxquestions.org/questions/programming-9/mkdir-naming-variable-4175489754/)

mkdir naming variable

I am trying to make a batch command set that will convert files from .NEF to .jpg and place them in a directory with the same name as the parent + jpg attached to the end within the parent directory.

Code:

mkdir $(name of parent directory + jpg) # ie /test would now contain /testjpg as a sub directory#; ufraw-batch --out-type=jpg *.NEF ; mv *.jpg testjpg

Running the command set in a directory called photos with files 001.NEF, 002.NEF would create directory photosjpg within photos containing the files 001.jpg and 002.jpg. The original .NEF files would remain in photos.

I am not sure I follow 100% but are you looking for something like:

Code:

mkdir "${PWD}jpg"

that makes testjpg a sister directory to test, not a child of test which is what I want, but many thanks

Nef is propriety used on nikon slrs, how will you get the conversion done? I don't think a simple rename will work.

Quote:

Originally Posted by ericson007 (Post 5089970)

Nef is propriety used on nikon slrs, how will you get the conversion done? I don't think a simple rename will work.

it is not a simple rename and the part you are talking about works. I am interested in something along the lines of

Code:

home$:mkdir "${PWD}jpg"

nikon is sorted. thanks

Quote:

that makes testjpg a sister directory to test, not a child of test which is what I want, but many thanks

Actually that is incorrect. $PWD stores the name of the directory you are in, hence issuing the command would result in a directory being created as a child

Quote:

Originally Posted by grail (Post 5090004)

Actually that is incorrect. $PWD stores the name of the directory you are in, hence issuing the command would result in a directory being created as a child

I know what you are saying and I agree with you but I am passing on what I am getting. I am issuing the command from within the directory /home/test and it is creating /home/testjpg.

Code:

Study@Study:~$ ls

Accounts        Library                test

Calibre Library  Mail                    The Blues Brothers (1980) [1080p]

Desktop          Music                  The Usual Suspects

Documents        MUSIX_GNU+Linux_3.0rc1  vids

Downloads        MyMachines              VirtualBox VMs

Dropbox          Pictures                workspace

Holidays        Scrabble                

Jobs            Shared

kde3-backup      sketchbook

Study@Study:~$ cd test

Study@Study:~/test$ mkdir "${PWD}jpg"

Study@Study:~/test$ ls

tect.txt

Study@Study:~/test$ ls ..

Accounts        Library                test

Calibre Library  Mail                    testjpg

Desktop          Music                  The Blues Brothers (1980) [1080p]

Documents        MUSIX_GNU+Linux_3.0rc1  The Usual Suspects

Downloads        MyMachines              vids

Dropbox          Pictures                VirtualBox VMs

Holidays        Scrabble                workspace

Jobs            Shared                  

kde3-backup      sketchbook

Study@Study:~/test$

Sorry .. I forgot about the full path being there :(

Try:

Code:

mkdir "${PWD##*/}jpg"

Quote:

Originally Posted by grail (Post 5090025)

Sorry .. I forgot about the full path being there :(

Try:

Code:

mkdir "${PWD##*/}jpg"

thank you that worked what does the ##*/ do

Search on this page for ${var##Pattern}