memset vs char arr initialization
 

just a bit curious to ask...

given uint8_t block[25];

is

memset(block, '\0', 25);

equivalent to

for (i=0; i<25; i++)
block[i] = '\0';

?

Hello,
There is one mistake though in what u hav typed. memset takes second argument as an integer so typically that has to be
memset(block,0,25);
Having said that , the behaviour is the same in both cases.

Regards,
S.Suresh Stephen.

Arh.. ok, thanks for pointing that out, but why does glibc spec describes

void * memset (void *block, int c, size_t size) Function
This function copies the value of c (converted to an unsigned char) into each of the first size bytes of the object beginning at block. It returns the value of block.

Hi,
The memset function will behave in such a manner after setting the value it would return a void pointer to that block which can be type casted into a char* , but take both arrays and check it up , both will have the same contents.

Regards,
S.Suresh Stephen

In C, it doesn't matter whether you write
memset(block,0,25);
or
memset(block,'\0',25);

memset vs. loop: The result is the same, but typically memset is highly tuned, so that it executes much faster for large buffers.