LinuxQuestions.org - [SOLVED] Matching double quotes "

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hattori.hanzo

11-23-2010 05:52 AM

Matching double quotes "

Code:

Dhcp Server 190.21.12.50 add scope 190.21.12.0 255.255.255.0 "New York" ""

I am using this to extract the network and mask.

Code:

grep "add scope" file | cut -d" " -f6,7

What would one use to extract the Description between the double quotes?

Thanks & Regards,

catkin

11-23-2010 05:59 AM

Code:

grep "add scope" file | cut -d'"' -f2

sycamorex

11-23-2010 06:02 AM

awk -F\" '{print $2}' file
or
awk -F\" '{print $2,$4}' file
To match the contents of the second double quotes

hattori.hanzo

11-23-2010 06:43 AM

Thanks for the input but is it possible to accomplish this in one line.

I guess I could run it thru twice then combine the output.

Quote:

grep "add scope" file | cut -d" " --output-delimiter="/" -f6,7
grep "add scope" file | cut -d'"' -f2

Thanks & Regards,

grail

11-23-2010 06:58 AM

How about:

Code:

sed -r '/add scope/s@.*scope ([^ ]+) ([^ ]+) "([^"]+)".*@\1/\2 \3@' file

colucix

11-23-2010 07:06 AM

Using awk (as previously suggested by sycamorex):

Code:

$ awk -F\" '/add scope/{n = split($1,_," "); printf "%s/%s %s\n", _[6], _[7], $2}' file

190.21.12.0/255.255.255.0 New York

colucix

11-23-2010 07:07 AM

Quote:

Originally Posted by grail (Post 4168135)

How about:

Code:

sed -r '/add scope/s@.*scope ([^ ]+) ([^ ]+) "([^"]+)".*@\1/\2 \3@' file

Hi grail! Nice sed one-liner! :)

hattori.hanzo

11-24-2010 12:49 AM

Thanks guys. I will need to study both sed and awk solutions.

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