makefile for debug and release version

nikoladsp · 04-27-2007, 03:46 AM

hi,
i would like to write one Makefile with capabilities to build debug and release version of one program, ie:

Code:

CC		= g++
BIN		= ./bin
CFLAGS	        = -Wall
RM		= rm -rf

	
debug: main.cpp
	CFLAGS="$CFLAGS -g -ggdb3"
	$(CC) $(CFLAGS) -o $(BIN)/cygtestd main.cpp
	
release: main.cpp
	CFLAGS="$CFLAGS -O2"
	$(CC) $(CFLAGS) $(BIN)/cygtest main.cpp
	
clean:
	$(RM) $(BIN)/*.o $(BIN)/*.exe

or something like this...i consulted GNU Makefile, without success

can somebody help?

10x in advance...

ps
i am using eclipse + cygwin.

nikoladsp · 04-27-2007, 04:30 AM

i will reply to myslef, but with another 2 questions

Code:

CC	= g++
CFLAGS	= -Wall
RM	= rm -rf

BIN	= ./bin
OUT	= 
DEBUG 	= yes

ifeq ($(DEBUG),yes)
	CFLAGS += -ggdb3
	OUT = $(BIN)/cygtestd.exe
else
	CFLAGS += -O2
	OUT = $(BIN)/cygtest.exe
endif
	 
all: main

main: main.o
	$(CC) $(BIN)/main.o -o $(OUT)
	
main.o: main.cpp
	$(CC) $(CFLAGS) -c main.cpp -o $(BIN)/main.o

clean:
	$(RM) $(BIN)/*.o $(OUT)

1. is this solution is OK to use?
2. how to make case-insensitive comparation in ifeq(...)?

10x