Little Bash Script help

ryme27 · 11-03-2010, 09:22 AM

The script should list the disk storage occupied by each immediate subdirectory of a given argument or the current directory with the subdirectory names sorted in ABC order.
Also, list the name of the subdirectory with the highest disk usage along with its storage size.
If more than one subdirectory has the same highest disk usage, list any one of those subdirectories. Include meaningful brief comments.

This is what i have so far. When i use the head for some reason it wont show the name of the largest directory but the tail shows the name of the smallest and size. Any Help PLS?

Code:

# Display the Directories #


function list {
echo Disk space use (in KB) for each subdirectory
du --max-depth=1
}

fuction first {
echo Largest File
list | sort -n -r | head -n 1
 }

function last {
echo Smallest File
list | sort -n -r | tail -n 1
}

catkin · 11-03-2010, 10:30 AM

Please show your whole script. What is the list command? An alias?

ee437 · 11-03-2010, 11:49 AM

i don't know if this is helpful, but, did you copy and paste the code?

function is spelled incorrectly -- fuction -- in the "first" function.

genderbender · 11-04-2010, 06:30 AM

Quote:

Originally Posted by ryme27

This is what i have so far. When i use the head for some reason it wont show the name of the largest directory but the tail shows the name of the smallest and size. Any Help PLS?

Yes - Your du includes the '.' directory (the entire contents of the current working directory). The head command will list the first line that matches (thus the total of your current directly) your tail will echo the last line that matches (thus matching the smallest directory). As your . directly will always be bigger than all the directories contained within it, it will always be the first match. There's a bunch of solutions to this (using head -2 is probabyl the easiest). I'm sure du has options to ignore parent as well