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Old 11-02-2004, 04:40 AM   #1
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Registered: Sep 2004
Posts: 2

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interrupts registrering

hello, I'm trying to register an interrupt handler. I'm running the following code:

i = 0;
while (i < 255)
printk(KERN_ERR MODULE_NAME ": i = %d.\n", i);
result = request_irq(i, irq_handler, 0, MODULE_NAME, (void *)(irq_handler));
if (result == 0)
{printk(KERN_ERR MODULE_NAME ": i = %d, request_irq succeeced. \n", i);
free_irq(i, NULL);}
printk(KERN_ERR MODULE_NAME ": i = %d, request_irq returned %d.\n", i, result);

I get the following output:
success: i = 4, 6, 9, 13
i< 16: request_irq() returns EBUSY (device or resource busy)
16 <= i < 224: request_irq() returns ENOSYS (function not implemented)
224 < i: request_irq() returns EINVAL (invalid argument)

The only thing I need is a way to intercept APIC interrupt (to allocate LVT entry). What can be wrong? Why can't I allocate LVT entry #153, for example?

I'm running SUSE 9.1, kernel 2.6.52 on Pentium-M machine

Thanks in advance for the replies


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