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Old 04-15-2009, 06:17 PM   #1
donpar
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Registered: Feb 2006
Location: Sunnyvale, CA
Distribution: RH Enterprise 5 and 6, RHEV 2.2
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In Python, printing leading zero for hex numbers 0 through f


Hello,

This is probably a simple question for an experienced Python person:

This is a little python program that gets 3 random hex numbers and prints them out:


import random

hn1 = (hex(random.randint(0,63))[2:])
hn2 = (hex(random.randint(0,255))[2:])
hn3 = (hex(random.randint(0,255))[2:])

print (hn1,":",hn2,":",hn3,sep="")


Example Result: 37:bc:31

All is fine & dandy except when the hex number is from 0 through f. In that case the result may be 7b:5:5c
I'd actually like it to be 7b:05:5c

Is there a simple way of formatting this?

Many thanks,

Don P
 
Old 04-15-2009, 07:09 PM   #2
rriggs
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Registered: Mar 2009
Location: Colorado, US
Distribution: Fedora 13, Fedora 14, RHEL6 Beta
Posts: 46

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Don't convert the numbers to hex strings with hex(). Use print formatting to format the numbers.

>>> print '%02X:%02X:%02X' % (12, 21, 129)
0C:15:81

Or

>>> hx='%02X:%02X:%02X' % (12, 21,129)
>>> print hx
0C:15:81

Regards
 
  


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